(3m+1)^2=7-(m+8)(m-3)

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Solution for (3m+1)^2=7-(m+8)(m-3) equation: 



(3m+1)^2=7-(m+8)(m-3)

We move all terms to the left:

(3m+1)^2-(7-(m+8)(m-3))=0

We multiply parentheses ..

-(7-(+m^2-3m+8m-24))+(3m+1)^2=0



We calculate terms in parentheses: -(7-(+m^2-3m+8m-24)), so:

7-(+m^2-3m+8m-24)

determiningTheFunctionDomain
-(+m^2-3m+8m-24)+7

We get rid of parentheses

-m^2+3m-8m+24+7

We add all the numbers together, and all the variables

-1m^2-5m+31

Back to the equation:

-(-1m^2-5m+31)



We get rid of parentheses

1m^2+5m+(3m+1)^2-31=0

We add all the numbers together, and all the variables

m^2+5m+(3m+1)^2-31=0

We move all terms containing m to the left, all other terms to the right

m^2+5m+(3m+1)^2=31

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